The left arm of the lever is 0.5 m, and the right one is 1.5 m. A force of 30 N acts on the left arm of the lever

| May 14, 2021 | education

The left arm of the lever is 0.5 m, and the right one is 1.5 m. A force of 30 N acts on the left arm of the lever. What force must be applied to the right side of the lever for the lever to be in balance?

Ll = 0.5 m.

Lp = 1.5 m.

Fl = 30 N.

Fп -?

The condition for the equilibrium of the lever is the equality of the moments of forces from the opposite sides of the lever: M1 = M2.

The moment of force M is called the product of the applied force F to the smallest distance from the application of force in the axis of rotation of the lever, which is called the arm L: M = F * L.

Fl * Ll = Fp * Lp.

The force Fп, which acts on the lever on the right side, will be determined by the formula: Fп = Fl * Ll / Lп.

Fп = 30 N * 0.5 m / 1.5 m = 10 N.

Answer: on the right side, a force Fп = 10 N. acts on the lever.



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