The legs a and b of a right triangle are given: 1) a = 6 cm, b = 8 cm,) 2a = 1 m, b = 1 m 3) a = 3/11 dm

The legs a and b of a right triangle are given: 1) a = 6 cm, b = 8 cm,) 2a = 1 m, b = 1 m 3) a = 3/11 dm, b = 4/11 dm 4) a = 2 , 3 cm, b = 4 cm, Find the hypotenuse.

Let’s find the hypotenuse of triangles according to the Pythagorean theorem (the sum of the squares of the legs is equal to the square of the hypotenuse):

1) a² + b² = c²;

6² + 8² = c²;

36 + 64 = c²;

c² = 100;

c = √100;

c = 10 cm.

2) a² + b² = c²;

0.5² + 1² = s²;

0.25 + 1 = s²;

c² = 0.25;

c = √0.25;

s = 0.5 m.

3) a² + b² = c²;

3 / 11² + 4 / 11² = s²;

9/121 + 16/121 = s²;

25/121 = s²;

c = √25 / 121;

s = 5/11 dm.

4) a² + b² = c²;

2.3² + 4² = c²;

5.29 + 16 = s²;

c² = 21.29;

s = √21.29 cm