The legs CT and CH of the right-angled triangle TCH are 15 dm and 20 dm, respectively.

The legs CT and CH of the right-angled triangle TCH are 15 dm and 20 dm, respectively. Find the height of this triangle, dropped by the hypotenuse.

1. SK – height. S – area.
2.S = TC x CH / 2 = 15 x 20: 2 = 150 decimeters.
3. Calculate the length of the TN hypotenuse using the Pythagorean theorem:
TH = √TC² + CH² = √15² + 20² = √225 + 400 = √625 = 25 decimeters.
4. Calculate the length of the SK height using another formula for calculating S:
S = TH x SK / 2.
SK = 2 x 150: 25 = 12 decimeters.
Answer: the length of the height SK = 12 decimeters.



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