The legs of a right-angled triangle are 12 cm and 16 cm. Calculate the height drawn to the hypotenuse.

1. Vertices of the triangle – A, B, C. Angle B – straight line. VK – height. S – area. The lengths of the legs AB and BC are 12 and 16 centimeters, respectively.

2. AB² + ВС² = АС² (along the tower of Pythagoras).

AC = √AB² + BC² = √12² + 16² = √144 + 256 = √400 = 20 centimeters.

3. S = BC x AB / 2 = 16 x 12: 2 = 96 centimeters².

4. We calculate the length of the height BK using another formula for calculating S:

S = AC x BK / 2. BK = 2 x 96: 20 = 9.6 centimeters.

Answer: height BK = 9.6 centimeters.



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