The legs of a right-angled triangle are 8 and 6. Find the sine of the smallest angle of this triangle.

The hypotenuse of this rectangle is:

√ (8 ^ 2 + 6 ^ 2) = 10.

The sine of the first angle is:

8/10 = 4/5;

The sine of the second angle is:

6/10 = 3/5;

Since, on the interval (0, pi / 2), the sine increases with increasing angle, the smallest angle will be at the sine with the smallest value.

Therefore, the sine of the smallest angle of this triangle is 3/5.