The legs of a right triangle are 2 and √ 12. Find the sine of the smaller angle of the triangle.

Let, by condition, be given a right-angled triangle ABC: AB is the hypotenuse, AC = 2 and BC = √12, the angle C = 90 degrees is a straight line.
Let us find the length of the hypotenuse by the Pythagorean theorem:
AB = √ (AC ^ 2 + BC ^ 2);
AB = √ (2 ^ 2 + (√12) ^ 2) = √ (4 + 12) = √16 = 4 (cm).
The sine of an angle is the ratio of the opposite leg to the hypotenuse.
Find the sine of angle A:
sinA = BC / AB = √12 / 4 = 2√3 / 4 = √3 / 2
sinA = √3 / 2 corresponds to an angle of 60 degrees, so angle A = 60 degrees.
Find the sine of angle B:
sinB = AC / AB = 2/4 = 1/2
sinB = 1/2 corresponds to an angle of 30 degrees, so angle B = 60 degrees.
angle A> angle B
Answer: sinВ = 1/2.