The length of a circle circumscribed about a square is 8pi cm. find the perimeter of the square.

The diagonal AC of the square ABCD is the diameter of the circumscribed circle around it.

The circumference is: L = 2 * π * R = 8 * π.

R = 8 * π / 2 * π = 4 cm.

Triangle AOB is rectangular and isosceles, then AB ^ 2 = 2 * R ^ 2.

AB = R * √2 = 4 * √2 cm.

Then Ravsd = 4 * AB = 16 * √2 cm.

Answer: The perimeter of the square is 16 * √2 cm.



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