The length of a rectangle is 5 times its width, find the sides of the rectangle if its perimeter is 1212 cm.

For a rectangle, the perimeter is twice the sum of the two adjacent sides:
P = 2 * (a + c),
where a is the length and c is the width.
Let for a given rectangle x cm is the width, then 5x cm is the length.
So the perimeter of the rectangle is:
2 * (x + 5x) = 1212.
To solve the equation you need:
– divide both sides of the equation by 2
x + 5x = 606;
– bring similar
6x = 606;
– divide both sides of the equation by 6
x = 101 (cm) – the length of the rectangle.
This means that the width of the rectangle is 5 * 101 = 505 cm.