The length of a rectangular parallelepiped is 12 cm, width 5 cm, height 9 cm, how much
The length of a rectangular parallelepiped is 12 cm, width 5 cm, height 9 cm, how much will the volume of the parallelepiped increase if each dimension is increased by 1 cm.
Let’s find what the volume of this parallelepiped is equal to.
According to the condition of the problem, the length of this rectangular parallelepiped is 12 cm, its width is 5 cm, and its height is 9 cm.
The volume of any rectangular parallelepiped is equal to the product of the length, width and height of this rectangular parallelepiped, therefore, the volume V1 of this parallelepiped is:
V1 = 12 * 5 * 9 = 60 * 9 = 540 cm ^ 3.
If each side of this parallelepiped is increased by 1 cm, then the length, width and height of the resulting parallelepiped will be 13 cm, 6 cm and 10 cm, respectively, and the volume v2 of the resulting parallelepiped will be:
V = 13 * 6 * 10 = 13 * 60 = 780 cm ^ 3.
Consequently, the volume of the parallelepiped will increase by 780 – 540 = 240 cm ^ 3.
Answer: the volume of the parallelepiped will increase by 240 cm ^ 3.