The length of one arm of the lever is 60 cm. The length of the other is 5 cm. A force of 100 N acts on the larger arm.
| November 23, 2020 | education
The length of one arm of the lever is 60 cm. The length of the other is 5 cm. A force of 100 N acts on the larger arm. What force must be applied to the smaller arm in order for the lever to be in balance?
Given:
L1 = 60cm
L2 = 5cm
F1 = 100 H
Find: F2 =?
Decision:
M1 = M2
L1 * F1 = L2 * F2
F2 = F1 * L1 / L2 = 100 * 50/5 = 1000 n
We can convert 1000n to 1kN
Answer: 1000 n (1kN)
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