The length of one of the lateral sides of a rectangular trapezoid is 25. Find the length of the largest of the bases
The length of one of the lateral sides of a rectangular trapezoid is 25. Find the length of the largest of the bases of this trapezoid, if it is known that a circle with a radius of 12 can be inscribed into it.
Since a circle is inscribed in the trapezoid, the sum of the lengths of its bases is equal to the sum of the lengths of the lateral sides. AB + СD = BC + AD.
The height of a rectangular trapezoid is equal to the diameter of the inscribed circle, then AB = CH = 2 * R = 24 cm, then СD, by condition, is 25 cm.
In a right-angled triangle СDН, according to the Pythagorean theorem, DН^2 = СD^2 – CH^2 = 625 – 576 = 49.
DН = 7 cm.
The perimeter of the trapezoid is: P = AB + СD + BC + AD = 24 + BC + 25 + AН + 7 = 98.
2 * BC = 98 – 56 = 42.
BC = 42/2 = 21 cm.
Then AD = 21 + 7 = 28 cm.
Answer: The length of the larger base is 28 cm.