# The length of one wire is 20 cm, the other 1.6 m. The cross-sectional area and material

The length of one wire is 20 cm, the other 1.6 m. The cross-sectional area and material of the wires are the same. Which wire has more resistance and how many times?

Initial data: l1 (length of the first wire) = 20 cm = 0.2 m; l2 (length of the second wire) = 1.6 m; S1 = S2 = S (wire cross-sectional area); ρ1 = ρ2 = ρ (resistivity of the wire material).

Since the resistance of the wire can be calculated using the formula: R = ρ * l / S, the ratio of the resistances of the selected wires is: R2 / R1 = l2 / l1.

Calculation: R2 / R1 = 1.6 / 0.2 = 8 times.

Answer: The resistance of the second wire is 8 times greater.

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