The length of the active part of the conductor is 15 cm. The angle between the direction of the current

| June 2, 2021 | education

The length of the active part of the conductor is 15 cm. The angle between the direction of the current and the induction of the magnetic field is 90 degrees. With what force does a magnetic field with an induction of 40 mT act on the conductor if the current in it is 12A?

According to Ampere’s law, the force that acts on the conductor is equal to:
F = I * B * L * sin a, where I is the current strength (I = 12 A), B is the value of the magnetic field induction (B = 40 * 10 ^ -3 T), L is the length of the conductor (L = 15 cm = 0.15 m), sin a is the angle between the vector of magnetic induction and the direction along which the current flows (sin a = sin 90 = 1).
Hence:
F = I * B * L * sin a = 12 * 40 * 10 ^ -3 * 0.15 * 1 = 0.072 H = 72 mN.
Check: H = A * T * m = A * (kg * s ^ -2 * A ^ -1) * m = kg * m / s ^ 2 = N.
Answer: The current is 72 mN.



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