The length of the base of the rectangular parallelepiped is 12 cm, and the width is three-fourths of the length

| January 15, 2021 | education

The length of the base of the rectangular parallelepiped is 12 cm, and the width is three-fourths of the length and three-fifths of the height. Find the surface area of this rectangular parallelepiped and its volume.

To solve this problem, remember that the volume of a rectangular parallelepiped is equal to the product of its three dimensions. Let’s calculate what the width of the parallelepiped is.
b = 3/4 * 12 = 36/4 = 9 centimeters.
Let’s calculate the height.
9: 3/5 = 9 * 5/3 = 45/3 = 15 centimeters.
Let’s calculate the surface area of a rectangular parallelepiped. The area of the rectangle is equal to the product of the length and the width. S = a * b, where a is the length and b is the width.
S = 2 * 12 * 9 + 2 * 12 * 15 + 2 * 15 * 9 = 216 + 360 + 270 = 846 sq. Cm.
Let’s calculate the volume.
V = 12 * 9 * 15 = 1620 cc.
Answer: 846 sq. Cm. 1620 cc



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