# The length of the broken line is 15 dm, the first link of the broken line is 1 dm and 8 cm longer than

The length of the broken line is 15 dm, the first link of the broken line is 1 dm and 8 cm longer than the second, and the third is 3 dm shorter than the second. Find the lengths of the links of the polyline.

Let the second link of the broken line be x dm.

The first link is 1 dm and 8 cm longer than the second, which means it has a length:

(x + 1.8) dm,

1 cm = 0.1 dm,

1 dm 8 cm = 1.8 dm.

The third link is 3 dm shorter than the second, which means it has a length:

(x – 3) dm.

The whole length of the broken line is 15 dm.

Let’s compose and solve the equation:

x + 1.8 + x + x – 3 = 15,

3x = 16.2,

x = 5.4 dm,

x + 1.8 = 5.4 + 1.8 = 7.2 dm,

x – 3 = 5.4 – 3 = 2.4 dm.

Answer: The broken line has links with a length of 7.2 dm, 5.4 dm and 2.4 dm.

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