The length of the chord is 48, and the distance from the center of the circle to this chord is 70, find the diameter of the circle.

Let’s draw 2 radii and points O (the center of the circle) to points A and B (the ends of the chord) T. to OA and OB – equal => Triangle AOB – isosceles with base AB. OH – the distance from the center to the chord => OH is perpendicular AB => OH – the height of the triangle (AOB-p / b) => OH – median => AH = 48/2 = 24 Consider the triangle OHA, m (By the Pythagorean theorem => ОА ^ 2 = OH ^ 2 + AH ^ 2 => OA ^ 2 = 576 + 4900 = 5476 => OA = 74. ОА – radius (See drawing) => Diameter = 74 * 2 = 148
Answer: 148