The length of the diagonals of the rhombus is 24cm and 32cm. Find the perimeter of the rhombus.

The diagonals of the rhombus, at the point of their intersection, are halved and intersect at right angles.

Then AO = CO = AC / 2 = 32/2 = 16 cm, BO = DO = BD / 2 = 24/2 = 12 cm.

The ABO triangle is rectangular, in which, according to the Pythagorean theorem, we determine the length of the hypotenuse AB. AB ^ 2 = AO ^ 2 + BO ^ 2 = 256 + 144 = 400.

AB = 20 cm.

In a rhombus, the lengths of all sides are equal, then Ravsd = AB * 4 = 20 * 4 = 80 cm.

Answer: The perimeter of the rhombus is 80 cm.



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