The length of the first rectangle is 20 cm, and the width is 15 cm. The width of the second rectangle is 3 cm

| January 9, 2021 | education

The length of the first rectangle is 20 cm, and the width is 15 cm. The width of the second rectangle is 3 cm less than the width of the first, and their areas are equal. Find the length of the second rectangle.

Let us first find the area of ​​one rectangular figure.
To do this, we multiply the numerical values ​​of its sides by each other.
20 x 15 = 300 cm².
Now let’s find the numeric value for the width of another rectangular shape.
To do this, subtract 3 cm from the numerical value of the width of the first rectangular figure of 15 cm.
15 – 3 = 12 cm.
Now let’s find the numerical value of the length of the second rectangular shape.
To do this, divide the found area of ​​300 cm² by the found numerical value of the width of the second rectangular figure 12 cm.
300: 12 = 25 cm.
Answer: The numerical value of the length of the second rectangular figure is 25 cm.



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