# The length of the first rectangle is 3.6 m and the width is 2.4 m, the length of the second rectangle is 4.8 m.

The length of the first rectangle is 3.6 m and the width is 2.4 m, the length of the second rectangle is 4.8 m. Find the width of the second rectangle if the areas of the rectangles are known to be equal. Solve the problem by making a proportion.

Let’s denote the lengths of the sides of the first rectangle A1 = 3.6 m and B1 = 2.4 m, and the sides of the second rectangle A2 = 4.8 m and B2. Areas of rectangles S1 and S2, where S1 = S2.

Let’s write the formulas for the areas of two rectangles.

S1 = A1 * B1.

S2 = A2 * B2.

Divide the first equality by the second and get the proportion.

S1 / S2 = (A1 * B1) / (A2 * B2).

Substitute the values and calculate B2.

1 = (3.6m * 2.4m) / (4.8m * B2).

4.8 m * B2 = 3.6 m * 2.4 m.

B2 = (3.6 * 2.4 / 4.8) m.

B2 = (3.6 / 2) m.

B2 = 1.8 m.

Answer: The width of the second rectangle is 1.8 m.

One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.