The length of the first rectangle is 3.6 m and the width is 2.4 m, the length of the second rectangle is 4.8 m.

| May 28, 2021 | education

The length of the first rectangle is 3.6 m and the width is 2.4 m, the length of the second rectangle is 4.8 m. Find the width of the second rectangle if the areas of the rectangles are known to be equal. Solve the problem by making a proportion.

Let’s denote the lengths of the sides of the first rectangle A1 = 3.6 m and B1 = 2.4 m, and the sides of the second rectangle A2 = 4.8 m and B2. Areas of rectangles S1 and S2, where S1 = S2.

Let’s write the formulas for the areas of two rectangles.

S1 = A1 * B1.

S2 = A2 * B2.

Divide the first equality by the second and get the proportion.

S1 / S2 = (A1 * B1) / (A2 * B2).

Substitute the values and calculate B2.

1 = (3.6m * 2.4m) / (4.8m * B2).

4.8 m * B2 = 3.6 m * 2.4 m.

B2 = (3.6 * 2.4 / 4.8) m.

B2 = (3.6 / 2) m.

B2 = 1.8 m.

Answer: The width of the second rectangle is 1.8 m.



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