The length of the first rectangle is 40 centimeters; the width is 15 meters; the width of 2 rectangles is 5 centimeters

The length of the first rectangle is 40 centimeters; the width is 15 meters; the width of 2 rectangles is 5 centimeters larger than the width of the first, and their area was equal to S. Find the length of the second rectangle.

Let’s calculate the area of the first rectangle, provided that its length is 40 cm and width = 15 cm, according to the formula:
S = a * b = 40 * 15 = 600 cm².

The width of the second such figure is 5 cm larger, therefore:
b = 15 + 5 = 20 cm.

Let us express the length if the areas of the two figures are equal, that is, S = 600 cm². To find the first factor, divide the product by the second:
a = S: b = 600: 20 = 30 cm.