Initial data: a (length of the iron sheet) = 1 m; b (width of the iron sheet) = 80 cm; h (iron sheet thickness) = 1 mm.
Constants: according to the condition ρ (iron density) = 7800 kg / m ^ 3.
SI system: b = 80 cm = 80/100 m = 0.8 m; h = 1 mm = 1/1000 m = 0.001 m.
The weight of the iron sheet can be calculated using the formula: m = ρ * V, where V (volume of the iron sheet) = a * b * h.
The formula will take the form: m = ρ * a * b * h.
Let’s perform the calculation:
m = 7800 * 1 * 0.8 * 0.001 = 6.24 kg.
Answer: The mass of this iron sheet is 6.24 kg.
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.