The length of the iron sheet is 1 m, the width is 80 cm, and the thickness is 1 mm. Determine its mass.

Initial data: a (length of the iron sheet) = 1 m; b (width of the iron sheet) = 80 cm; h (iron sheet thickness) = 1 mm.

Constants: according to the condition ρ (iron density) = 7800 kg / m ^ 3.

SI system: b = 80 cm = 80/100 m = 0.8 m; h = 1 mm = 1/1000 m = 0.001 m.

The weight of the iron sheet can be calculated using the formula: m = ρ * V, where V (volume of the iron sheet) = a * b * h.

The formula will take the form: m = ρ * a * b * h.

Let’s perform the calculation:

m = 7800 * 1 * 0.8 * 0.001 = 6.24 kg.

Answer: The mass of this iron sheet is 6.24 kg.




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