The length of the iron wire is 100 m, the cross-sectional area is 2 mm ^ 2, the current strength

The length of the iron wire is 100 m, the cross-sectional area is 2 mm ^ 2, the current strength is 10 amperes. what is the voltage at the ends of this wire (if the specific resistance of iron is 0.1 Ohm * mm ^ 2 / m)

According to Ohm’s Law:
U = I * R, where U is the voltage at the ends of the iron wire (V), I is the current in the iron conductor (I = 10 A), R is the resistance of the iron wire (Ohm).
R = ρ * l / S, ρ is the specific resistance of the iron wire (ρ = 0.1 Ohm * mm ^ 2 / m), l is the length of the iron wire (l = 100 m), S is the cross-sectional area of the iron wire (S = 2 mm ^ 2).
Let’s calculate the voltage at the ends of the iron wire:
U = I * R = I * ρ * l / S = 10 * 0.1 * 100/2 = 500 V.
Answer: The voltage at the ends of the iron wire is 500 V.