The length of the minute hand of the tower clock is 4.5 m. How fast is the end of the arrow moving?

The speed of movement of the end of the minute hand of the tower clock can be calculated by the formula:

V = 2Π * R / T, where R is the length of the tower minute hand, radius (R = 4.5 m), T is the period of rotation of the end of the minute hand (T = 60 min = 60 * 60 = 3600 s).

Let’s calculate the speed of movement of the end of the minute hand of the tower clock:

V = 2Π * R / T = 2 * 3.14 * 4.5 / 3600 = 0.00785 m / s = 7.85 * 10-³ m / s.

Answer: The end of the hand of the tower clock moves at a speed of 7.85 * 10-³ m / s.