The length of the outer circumference of the front wheel of the carriage is 2.8 m, and the rear wheel is 4.4 m.
| January 5, 2021 | education
The length of the outer circumference of the front wheel of the carriage is 2.8 m, and the rear wheel is 4.4 m. What is the distance traveled by the carriage if its front wheel has made 200 more revolutions than the rear?
To determine the distance, you can determine the number of revolutions of the large rear wheel made and then multiply this number by the length of the outer circumference. Let us denote by n – the number of revolutions of the rear wheel made, x – the distance traveled. Then the equations are true: 4.4 * n = x and 2.8 * (n + 200) = x
You can write:
4.4 * n = 2.8 * (n + 200)
4.4 * n – 2.8 * n = 560
1.6 * n = 560
n = 350
Therefore, the path: x = 4.4 * 350 = 1540 m
Answer: the carriage traveled 1540 meters.
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