The length of the playground is 18 m and the width is one-sixth of the length of how many coils of 7 m

The length of the playground is 18 m and the width is one-sixth of the length of how many coils of 7 m of wire will be needed to enclose this playground with a double layer of wire.

The solution of the problem:
1. Find out what the width of the playground is equal to.
18 * 1/6 = 3 meters.
2. Let’s calculate the perimeter of the playground.
(18 + 3) * 2 = 21 meters.
3. How many coils of wire will be needed to enclose the site?
21/7 = 3 skeins.
Let’s answer the question of the problem.
3. Determine how many coils of wire will be needed to shield this area with a double layer of wire.
3 * 2 = 6 skeins.
Answer: It will take six skeins of wire to enclose the playground with a double layer of wire.