The length of the rectangle 14 dm is 6 dm more than its width, find the area of the square whose

The length of the rectangle 14 dm is 6 dm more than its width, find the area of the square whose side is equal to the width of the rectangle.

Find the width of the rectangle, for this we subtract 6 dm from the length of the rectangle, equal to 14 dm.

b = 14 dm – 6 dm = 8 dm.

The side of the square is equal to the width of the rectangle and is equal to 8 inches.

Let’s calculate the area of the square, raise to the second power the length of the side of the square.

S = (8 dm) ² = 64 dm².

Answer: the area of the square is 64 dm².



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