The length of the rectangle is 1 dm2 cm, and the width is 2 times less than the length.

The length of the rectangle is 1 dm2 cm, and the width is 2 times less than the length. Calculate the perimeter of this rectangle and the area.

Let’s find the width of the rectangle, provided that it is 2 times shorter than its length, equal to 1 dm 2 cm.
Let’s do the division:
1 dm 2 cm: 2 = 0.5 dm 1 cm, which is 6 cm (1 dm = 10 cm).
The sum of all sides of such a figure (perimeter) is calculated by the formula:
P = 2a + 2b = 2 * 12 + 2 * 6 = 24 + 12 = 36 cm or 3 dm 6 cm.
Let’s define the area by the formula:
S = a * b = 12 * 6 = 72 cm².