The length of the rectangle is 10 cm and the width is 2 times less. The rectangle was calculated by its perimeter and area.

The length of the rectangle (a) is 10 cm;

The width of the rectangle (b) is? cm, 2 times less than a;

Perimeter (Ppr.) -? cm;

Area (Sp.) -? cm ^ 2.

The first step is to calculate the length of the given rectangle. To do this, reduce its width by 2 times:

1) b = a: 2 = 10: 2 = 5 (cm).

The perimeter of a rectangle is determined by the formula:

Ppr. = (a + b) * 2.

The area of ​​the rectangle is determined by the formula:

Sp. = a * b.

Substitute the known values ​​of the length and width into these formulas and get the desired values ​​for the perimeter and area:

Ppr. = (10 + 5) * 2 = 15 * 2 = 30 (cm).

Sp. = 10 * 5 = 50 (cm ^ 2).

Answer: the perimeter is 30 cm, the area is 50 cm ^ 2.