The length of the rectangle is 10 times its width. Find the area and perimeter of the rectangle

The length of the rectangle is 10 times its width. Find the area and perimeter of the rectangle if the width is 63 cm less than the length.

Let’s solve this problem using the equation.

Let the width of the rectangle be x centimeters, then the length of the rectangle is 10 * x centimeters. We know that the width is 63 centimeters less than the length. Let’s make the equation:

10 * x – x = 63;

x * (10 – 1) = 63;

x * 9 = 63 (in order to find an unknown factor, you need to divide the product by a known factor);

x = 63: 9;

x = 7 centimeters – the width of the rectangle;

7 * 10 = 70 centimeters – the length of the rectangle;

70 * 7 = 490 cm ^ 2 – the area of ​​the rectangle;

2 * (7 + 70) = 2 * 77 = 154 centimeters – the perimeter of the rectangle.

Answer: 490 cm ^ 2; 154 centimeters.