The length of the rectangle is 10 times its width Find the perimeter and area of the rectangle

The length of the rectangle is 10 times its width Find the perimeter and area of the rectangle if the width is 63 centimeters less than the length.

Let’s find the length and width of the given rectangle.

Let’s denote the width of the rectangle through x.

According to the condition of the problem, the length of this rectangle is 10 times its width, therefore, the length of this rectangle is 10x.

It is also known that the width of this rectangle is 63 centimeters less than its length, therefore, we can draw up the following equation:

x = 10x – 63.

Solving this equation, we get:

10x – x = 63;

9x = 63;

x = 63/9;

x = 7 cm.

Knowing the width of this rectangle, we find its length:

10x = 10 * 7 = 70 cm.

Find the perimeter P and the area S of this rectangle:

P = 2 * (70 + 7) = 2 * 77 = 154 cm;

S = 70 * 7 = 490 cm².

Answer: the perimeter of this rectangle is 154 cm; the area of ​​this rectangle is 490 cm².