The length of the rectangle is 12 dm, and the width is 3 times less. 1) Calculate the area

The length of the rectangle is 12 dm, and the width is 3 times less. 1) Calculate the area of this rectangle. 2) Calculate the perimeter of this rectangle.

The task:
the length of the rectangle is 12 dm,
width of the rectangle -?, 3 times smaller,
area of the rectangle -? dm ^ 2,
perimeter of the rectangle -? dm.
Solution:
1) find the width of the rectangle:
12: 3 = 4 dm;
2) define the area:
12 4 = 48 dm ^ 2;
3) calculate the perimeter:
(12 + 4) 2 = 32 dm.
Answer: the area of the rectangle is 48 dm ^ 2, the perimeter is 32 dm.



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