The length of the rectangle is 12 dm. This is 2 times more than the side of the square.

The length of the rectangle is 12 dm. This is 2 times more than the side of the square. The width of the rectangle is 8 dm shorter than its length. Which shape is larger and by how much area?

Brief record of the task:

rectangle:

length – 12 dm;

width – ? dm, 8 dm shorter;

square – ? dm ^ 2;

square:

side – ? dm, 2 times less than the length of the rectangle;

square – ? dm ^ 2;

comparison of the areas of figures.

1. Calculate the width of the rectangle:

12 – 8 = 4 dm.

2. Its area:

12 4 = 48 dm ^ 2.

3. Size of the side of the square:

12: 2 = 6 dm.

4. Its area:

6 6 = 36 dm ^ 2.

5. Let’s compare the values of the areas of the figures:

48 – 36 = 12 dm ^ 2.

Answer: the area of the rectangle is 12 dm ^ 2 larger.