The length of the rectangle is 120 dm. It is more than 60 dm wide. Find the perimeter and area of this rectangle.

First of all, we determine the width of the rectangle, provided that it is 60 dm less than its length, equal to 120 dm:
120 – 60 = 60 dm.

Since the opposite sides of such a figure are equal, their sum (perimeter) is calculated by the formula:
P = 2a + 2b.

Substitute the measurements and write the expression:

P = 2 * 120 + 2 * 60 = 240 + 120 = 360 dm.

The area corresponds to:
S = a * b = 120 * 60 = 7200 dm².