The length of the rectangle is 12cm and the width is 4cm less. Find the area and perimeter

The length of the rectangle is 12cm and the width is 4cm less. Find the area and perimeter of the rectangle. Find the area of a square that has the same perimeter.

1) The width of the rectangle is 4 cm less than its length, which is 12 cm, which is:

12 – 4 = 8 cm.

The perimeter is calculated using the formula:

P = 2a + 2b = 2 * 12 + 2 * 8 = 24 + 16 = 40 cm.

The area of a rectangle whose opposite sides are equal corresponds to:

S = a * b = 12 * 8 = 96 cm².

2) The perimeter of the square is the same and equal to 40 cm, determined by the formula:

P = 4a. Let’s express the side:

a = P: 4 = 40: 4 = 10 cm.

Find the area:

S = a² = 10² = 100 cm².