The length of the rectangle is 12dm, this is 2 times the side of the square, the width is 8 cm less than its length

The length of the rectangle is 12dm, this is 2 times the side of the square, the width is 8 cm less than its length. Which fiura area is larger and by how much.

1. It is known that 1 dm = 10 cm.

2. Let us calculate the side of the square if, according to the problem statement, it is 2 times less than the length of the rectangle, equal to 12 dm.

12 dm: 2 = 6 dm = 60 cm.

3. Find the area of the square.

60 cm * 60 cm = 3600 cm ^ 2.

4. Let’s calculate the width of the rectangle if it is 8 cm less than its length.

12 dm – 8 cm = 120 cm – 8 cm = 112 cm.

5. Determine the area of the rectangle.

120 cm * 112 cm = 13440 cm ^ 2.

6. Find how much the area of the rectangle is greater than the area of the square.

13440 cm ^ 2 – 3600 cm ^ 2 = 9840 cm ^ 2 = 98 dm ^ 2 40 cm ^ 2.

Answer: The area of the rectangle is 98 dm ^ 2 40 cm ^ 2 larger than the area of the square.

1. It is known that 1 dm = 10 cm.

2. Let us calculate the side of the square if, according to the problem statement, it is 2 times less than the length of the rectangle, equal to 12 dm.

12 dm: 2 = 6 dm = 60 cm.

3. Find the area of the square.

60 cm * 60 cm = 3600 cm ^ 2.

4. Let’s calculate the width of the rectangle if it is 8 cm less than its length.

12 dm – 8 cm = 120 cm – 8 cm = 112 cm.

5. Determine the area of the rectangle.

120 cm * 112 cm = 13440 cm ^ 2.

6. Find how much the area of the rectangle is greater than the area of the square.

13440 cm ^ 2 – 3600 cm ^ 2 = 9840 cm ^ 2 = 98 dm ^ 2 40 cm ^ 2.

Answer: The area of the rectangle is 98 dm ^ 2 40 cm ^ 2 larger than the area of the square.