The length of the rectangle is 13 meters longer than its width The area of the rectangle is 140 cm2
The length of the rectangle is 13 meters longer than its width The area of the rectangle is 140 cm2 Find an example of the perimeter of the rectangle.
Let x be the width of the rectangle. Since the length of the rectangle is 13 meters longer than its width, the length of the rectangle is 13 + x. The area of the rectangle is equal to the product of length and width: S = a * b. Since the area of this rectangle is 140 square meters, substituting the values into the formula, we get: 140 = x * (13 + x),
x ^ 2 + 13x – 140 = 0. D = b ^ 2 – 4ac = 132 – 4 · 1 · (-140) = 169 + 560 = 729. Since the discriminant is greater than zero, the quadratic equation has two real roots:
x1 = (-13 – √729) / 2 1 = -20,
x2 = (-13 + √729) / 2 1 = 7.
The width of the rectangle is 7 m, and the length is 13 + 7 = 20 m. The perimeter of the rectangle is equal to the sum of all its sides. Since the opposite sides of the rectangle are equal, then P = 2 * a + 2 * b = 2 * 7 + 2 * 20 = 14 + 40 = 54 m.