The length of the rectangle is 16 cm, and the width is 2 times less. Find the area of the rectangle.

Find the width of the given rectangle.

According to the condition of the problem, the length of this rectangle is 16 cm, and its width is 2 times less, therefore, the width of this rectangle is:

16/2 = 8 cm.

Find the area S of a given rectangle as the product of the length and width of a given rectangle:

S = 16 * 8 = 128 cm².

Answer: the area of this rectangle is 128 cm².



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