The length of the rectangle is 16dm, and the width is 2/8 of the length of the rectangle.

The length of the rectangle is 16dm, and the width is 2/8 of the length of the rectangle. Find the perimeter and area of the rectangle.

Find the width of the rectangle:

16 * 2/8 = 4 dm;

Let’s find the perimeter, that is, the sum of the lengths of all sides of the rectangle:

16 + 16 + 4 + 4 = 40 dm;

Find the area, that is, the product of length and width:

16 * 4 = 64 dm ^ 2;

Answer: the perimeter is 40 dm, and the area is 64 dm ^ 2.