The length of the rectangle is 1m 48cm, and the width is 2 times less

The length of the rectangle is 1m 48cm, and the width is 2 times less, find the side of the square whose perimeter is equal to the perimeter of this rectangle.

For the convenience of the solution, we first translate the length of the rectangle into centimeters.

Since there is 100 cm in 1 meter, we get:

1 m 48 cm = 1 * 100 + 48 = 148 cm.

Find the width of the rectangle.

We divide the length by the specified difference.

148/2 = 74 cm.

Determine the perimeter of the rectangle.

To do this, multiply the sum of its length and width by 2 parts.

Will be:

2 * (148 + 74) = 444 cm.

Determine the length of the side of the square with the given perimeter.

To do this, we divide the perimeter into 4 parts, since all sides of the square are equal to each other.

444/4 = 111 cm.

Answer: 111 cm.



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