The length of the rectangle is 27 cm more than the width, find the area if the perimeter is 110 cm.

Let’s solve this problem using the equation.

Let the width of the rectangle be x centimeters, then the length of the rectangle is (x + 27) centimeters. By the condition of the problem, the perimeter is 110 centimeters. Let’s compose and solve the equation:

x + x + x + 27 + x + 27 = 110;

4x + 54 = 110;

4x = 110 – 54;

4x = 56;

x = 56: 4;

x = 14 centimeters – the width of the rectangle;

14 + 27 = 41 centimeters – the length of the rectangle;

14 * 41 = 574 cm ^ 2 – the area of the rectangle.

Answer: the area of the rectangle is 574 cm ^ 2.