The length of the rectangle is 3 meters 6 decimetres and the width is 1 meter 8dm

The length of the rectangle is 3 meters 6 decimetres and the width is 1 meter 8dm less than the length. Find the perimeter and area of the rectangle.

1) 3 m 6 dm – 1 m 8 dm = 36 dm – 18 dm = 18 dm = 1 m 8 dm.
In order to find the difference in these values, you must first bring them to the same units of measurement, for this you need to know that 1 m = 10 dm:
3 m 6 dm = 36 dm; 1 m 8 dm = 18 dm.
The perimeter is the sum of all sides.
P = 2 * (a + b), where P is the perimeter of the rectangle, a is the length of the rectangle, in is the width of the rectangle
2) 2 * (3 m 6 dm + 1 m 8 dm) = 2 * 4 m 14 dm = 2 * 5 m 4 dm = 10 m 8 dm;
S = a * b
3) 3 m 6 dm * 1 m 8 dm = 36 dm * 18 dm = 648 dm ^ 2 = 6.48 m ^ 2.
Answer: 10 m 8 dm and 6.48 m ^ 2.