# The length of the rectangle is 3 times its width, and the perimeter is 80 m. Find the area of the rectangle.

According to the condition of the problem, we know the perimeter of the rectangle, which is 80 m. We need to find the sum of the length and width of the rectangle. To do this, divide the perimeter in half:

80: 2 = 40 (m).

Let’s denote the width of the rectangle as x m.

The length of the rectangle from the condition of the problem is 3 times its width, therefore, the length of this rectangle is 3 x m.

Let’s compose and solve the equation if the sum of the length and width is 40 m:

x + 3 x = 40.

4 x = 40.

x = 40: 4.

x = 10.

Thus, we found the width of the rectangle to be 10 m.

Now let’s calculate the length of the rectangle by increasing the width value by 3 times:

10 * 3 = 30 (m).

Since we know the lengths of the two sides of the rectangle, we calculate its area. To do this, we multiply the length by the width:

S = 10 * 30 = 300 (m²).

Let us express the resulting area in ara: 300 m2 = 3 a (since 1 ap = 100 m2).

Answer: the area of a given rectangle is 3 aram.