The length of the rectangle is 3 times its width. By what percentage will the perimeter
The length of the rectangle is 3 times its width. By what percentage will the perimeter of the rectangle decrease by 20% and its width by 40%?
Let’s denote the width of this rectangle through x.
According to the condition of the problem, the length of this rectangle is 3 times its width, therefore, the length of this rectangle is 3x, and the perimeter P of this rectangle is:
P = 2 * (3x + x) = 2 * 4x = 8x.
If its given rectangle is reduced by 20%, and the width by 40%, then the length of the resulting rectangle will be 0.8 * 3x = 2.4x, the width of the resulting rectangle will be 0.6x, and the perimeter of the resulting rectangle will be:
2 * (2.4x + 0.6x) = 2 * 3x = 6x.
Therefore, the perimeter of the rectangle will decrease by:
100 * (8x – 6x) / 8x = 100 * 2x / 8x = 100/4 = 25%.
Answer: The perimeter of the rectangle will decrease by 25%.