The length of the rectangle is 5.48 m longer than its width, and the perimeter of the rectangle is 64.8 m.

The length of the rectangle is 5.48 m longer than its width, and the perimeter of the rectangle is 64.8 m. Find the area of the rectangle.

Given:
Rectangle A = 5.48> than B P = 64.8 m
S =?
Decision:
P = (A + B) * 2 (formula) Let side B be x, then side A is (x + 5.48) 64.8 = (x + 5.48 + x) * 2; 32.4 = (x + 5.48 + x); 26.92 = 2x; x = 26.92: 2; x = 13.46 S = A * B S = 13.46 * 18.94 S = 254.9
Answer: 254.9.



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