The length of the rectangle is 5 times its width. Find the sides of the rectangle if its perimeter is 1212cm.

According to the condition of the assignment, we find the sides of the rectangle, provided that one is 5 times larger than the other, and the sum of all of them = 1212 cm.

We know that the formula for determining the perimeter looks like this:

P = 2a + 2b.

Let us write down the equations for it, substituting the known values, for x we take the smallest side:

2 * 5x + 2x = 1212.

On the left side of the equation, we perform actions with the coefficients of the variable:

12x = 1212.

The second factor is the quotient of the first.

x = 1212: 12 = 101.

Therefore, width = 101 cm and length = 5 * 101 = 505 cm.