The length of the rectangle is 5 times its width. What is the area of this rectangle if its width is 8cm less than its length?

We will solve this problem using two conditional variables “X” and “Y”, equal to the length and width of the rectangle, respectively.

At the next stage, taking into account the conditions of the example, we compose the equations:

1) X / Y = 5;

2) X – Y = 8.

As a result of solving this system, we have X = 5U.

Substituting X into the second equation, we have 5Y – Y = 8 or 4Y = 8 or Y = 8/4 = 2 centimeters.

This means that the length of the rectangle will be 5 x 2 = 10 centimeters.

Therefore, the area of the rectangle is 2 x 10 = 20 cm ^ 2.

Answer: 20 cm ^ 2.