The length of the rectangle is 5cm and the width is 2cm more. Find the area and perimeter of the rectangle.

1) Find the width of the rectangle.
Let’s denote by the letter a – the length of the rectangle, and by the letter b – the width.
The problem statement says that the width of the rectangle is 2 cm more than the length. If we say that one value is “by” several units more or less than another, then we are talking about addition or subtraction. In our case, we are talking about addition. Let’s find the width of the rectangle:
b = 5 + 2 = 7 cm.
2) Find the perimeter of the rectangle.
The perimeter of any geometric figure is the sum of the lengths of its sides.
The perimeter of a rectangle is the sum of the length and width of the rectangle multiplied by 2. Let’s write the formula:
P = (a + b) × 2,
Substituting the known values ​​into the formula, we find the perimeter:
P = (5 + 7) × 2 = 12 × 2 = 24 cm.
3) Find the area of ​​the rectangle.
The area of ​​a rectangle is the product of the lengths of its sides. Let’s write the formula for the area:
S = a × b,
S = 5 × 7 = 35 cm².
Answer: the perimeter of the rectangle is 24 cm, and the area is 35 cm².