The length of the rectangle is 6 m and the width is 2 m less. 1) find the sign of this rectangle 2.find the area of this rectangle

Given:
The length a of the rectangle is 6 meters.
The width b of the figure is 2 meters less than its length a.

Let’s calculate the width b:
b = a – 2 = 6 – 2 = 4 meters.
Find the perimeter of the quadrangle by the formula P = a + a + b + b:
P = a + a + b + b = 6 + 6 + 4 + 4 = 20 meters.
We calculate the area of the figure using the formula S = a * b:
S = a * b = 6 * 4 = 24 m2.
Answer: P = 20 meters; S = 24 m2.