The length of the rectangle is 6m and the width is 50dm shorter. What is the perimeter of this rectangle?

First of all, we calculate the width of the rectangle, provided that it is 50 dm shorter than its length, equal to 6 m, which is:
6 – 5 = 1 m. Based on the fact that 1 m = 10 dm.
Let us determine the sum of all sides of such a figure, based on the formula:
P = 2a + 2b = 2 * 6 + 2 * 1. Find the products, then their sum:
P = 12 + 2 = 14 m – the perimeter of the rectangle.