The length of the rectangle is 7 3/5 cm. Its perimeter is equal to the perimeter
The length of the rectangle is 7 3/5 cm. Its perimeter is equal to the perimeter of the cadrat with a side of 6 cm. Find the width of the rectangle.
1. Given a square with side A equal to 6 cm.
Let’s find its perimeter.
A square has four sides equal to each other.
Therefore, the perimeter P = 4 * A = 4 * 6 = 24 cm.
2. A rectangle is specified.
By the condition of the problem, its perimeter is equal to the perimeter of a square with a side of 6 cm.
That is, the perimeter of the rectangle is also P = 24 cm.
It is known that its perimeter is calculated by doubling the sum of its length and width.
So this sum is equal to 24/2 = 12 cm.
3. The length of the rectangle is 7 3/5 or 38/5 cm.
Let’s find its width.
12 – 38/5 = 60/5 – 38/5 = 22/5 = 4 2/5 cm.
Answer: The width of the rectangle is 4 2/5 cm.